JEE Advanced levelOne or more correct optionsDifficulty 3 of 3td072
One mole of a monoatomic ideal gas is heated from 300K to 600K, once at constant volume and once at constant pressure. Use R=8.314Jmol−1K−1. Select the correct statement(s).
AThe heat absorbed at constant pressure is about 6.2kJ
BThe work done by the gas at constant pressure is about 2.5kJ
CΔU≈3.7kJ in both processes
DThe heat absorbed at constant volume is about 6.2kJ
Answer: A, B, C
ΔU=nCvΔT=1.5×8.314×300=3.7kJ for any path (ideal gas). At constant volume qV=ΔU=3.7kJ; at constant pressure qp=nCpΔT=2.5×8.314×300=6.2kJ and wby=nRΔT=2.5kJ. So the constant-volume heat is not 6.2kJ.