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JEE Main levelSingle correct optionDifficulty 2 of 3td063

One mole of an ideal gas expands against a constant external pressure of $1.00 bar$ from $10.0 L$ to $25.0 L$ . Taking $1 L bar = 100 J$ , the work done on the gas is

A $- 2.50 kJ$
B $+ 1.50 kJ$
C $- 1.50 kJ$
D $- 0.15 kJ$

Answer: C

w = - P_{e x t} Δ V = - 1.00 \times (25.0 - 10.0) L bar = - 15.0 L bar = - 1500 J = - 1.50 kJ

. The sign is negative because the gas does work on the surroundings.

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