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JEE Main levelNumerical answerDifficulty 2 of 3td062

Three moles of a diatomic ideal gas ( $C_{p} = \frac{7}{2} R$ ) are heated at constant pressure from $300 K$ to $400 K$ . Find the heat absorbed in $kJ$ (two decimals). Use $R = 8.314 J mo l^{- 1} K^{- 1}$ .

Numerical answer type, answer in kJ, tolerance 0.01.

Answer: 8.7297 kJ

At constant pressure

q_{p} = n C_{p} Δ T = 3 \times \frac{7}{2} \times 8.314 \times 100 J = 8.730 kJ

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