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JEE Main levelNumerical answerDifficulty 2 of 3td041

Two moles of a monatomic ideal gas are heated at constant volume from $300 K$ to $600 K$ . With $R = 8.314 J mo l^{- 1} K^{- 1}$ , the entropy change in $J K^{- 1}$ (two decimals) is

Numerical answer type, answer in J/K, tolerance 0.02.

Answer: 17.29 J/K

Δ S = n C_{V} ln (T_{2} / T_{1}) = 2 (1.5) (8.314) ln 2 = 17.288 J K^{- 1}

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