The flocculation value of $KCl$ for a positively charged sol is 36 mmol per litre of sol. What volume of 0.12 M $KCl$ solution is needed to coagulate 350 mL of the sol? Ignore the volume change on mixing (nearest integer in mL).

Numerical answer type, answer in mL, tolerance 0.5.

Answer: 105 mL

Moles needed

= 36 \times 0.350 = 12.6

mmol. Volume of 0.12 M solution

= 12.6/0.12 = 105 mL