Numerical answer type, answer in cycles, tolerance 0.1.
Answer: 4 cycles
Each cycle multiplies the concentration by V/(V+4V)=1/5. After n cycles c=0.50×5−n must be below 1.0×10−3, so 5n>500. n>log500/log5=(2+0.699)/0.699=3.86. The minimum integer is 4.