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JEE Advanced levelNumerical answerDifficulty 3 of 3sc048

A diatomic gas adsorbs with dissociation, so $θ = \frac{( K p ) ^{1/2}}{1 + ( K p ) ^{1/2}}$ . At a pressure $p_{1}$ the coverage is $0.40$ . Find the coverage when the pressure is raised to $9 p_{1}$ (two decimals).

Numerical answer type, tolerance 0.01.

Answer: 0.6667

At

p_{1}

:

0.40 = a / (1 + a)

so

a = (K p_{1})^{1/2} = 0.40/0.60 = 0.6667

. At

9 p_{1}

:

a^{'} = 3 a = 2.000

, so

θ = 2.000/3.000 = 0.67

.

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