Gases A and B adsorb competitively on the same sites (competitive Langmuir): $θ_{A} = \frac{K _{A} p _{A}}{1 + K _{A} p _{A} + K _{B} p _{B}}$ . Given $K_{A} = 0.40 kP a^{- 1}$ , $p_{A} = 5.0 kPa$ , $K_{B} = 0.10 kP a^{- 1}$ , $p_{B} = 30 kPa$ , and a monolayer capacity $14 c m^{3} g^{- 1}$ (STP), find the volume of A adsorbed per gram in $c m^{3}$ (two decimals).

Numerical answer type, answer in cm^3, tolerance 0.02.

Answer: 4.6667 cm^3

K_{A} p_{A} = 2.0

and

K_{B} p_{B} = 3.0

θ_{A} = 2.0/ (1 + 2.0 + 3.0) = 0.3333

. Volume of A

= 0.3333 \times 14 = 4.67 c m^{3} g^{- 1}