The compound shown is one stereoisomer of 2,4-dibromopentane. Which statements are correct?

The two stereocentres C2 and C4 carry the same groups and have opposite descriptors, $R$ and $S$, so the compound is the meso form, (2R,4S)-2,4-dibromopentane, with a mirror plane through C3 perpendicular to the chain. C3 carries two hydrogens, so it cannot be a stereocentre of any kind and is not pseudoasymmetric (contrast 2,3,4-trichloropentane, where C3 carries H and Cl). The chiral (2R,4R) isomer differs from the meso form at only one centre, so the two are diastereomers.