The compound shown is 2,3-dibromobutane drawn with a definite configuration at both carbons. Which statement about it is correct?

The drawn stereoisomer is (2R,3S)-2,3-dibromobutane. Both C2 and C3 are stereocentres (each carries H, Br, $\mathrm{CH}{}_3$ and $\mathrm{CHBrCH}{}_3$), but the two halves of the molecule are mirror images of each other, so the molecule has an internal mirror plane (in the eclipsed conformation) and is superimposable on its mirror image. It is the meso form, which is achiral and optically inactive.