The compound shown is 3-methylpent-1-ene drawn without stereochemistry. Which of the following statements about it are correct?

C3 carries $\mathrm{H}$, $\mathrm{CH}{}_3$, $\mathrm{C}{}_2\mathrm{H}{}_5$ and the vinyl group $\mathrm{CH}=\mathrm{CH}{}_2$; these are four different groups, so C3 is a stereocentre and the molecule is chiral. The double bond is terminal ($\mathrm{CH}{}_2=$) and carries two identical $\mathrm{H}$ atoms on C1, so there is no geometrical isomerism. One stereocentre and no $E/Z$ element gives $2^1=2$ stereoisomers, a pair of enantiomers.