Answer: A
At C1: Br > C2 (Cl,C,H) > C3 (C,H,H) > H, and H points down. Viewed from above Br (outward), C2, C3 run clockwise, so C1 is R. At C2: Cl > C1 (Br,C,H) > C3 (C,H,H) > H, again H down. Viewed from above Cl (outward), C1, C3 run counter-clockwise, so C2 is S. The cis compound is (1R,2S) (confirmed by explicit CIP assignment); the trans compounds are (1R,2R)/(1S,2S).