Answer: D
Priorities at C3: C2 (=CH, duplicated C gives (C,C,H)) > C4 (C,H,H) > CH3 (H,H,H) > H. The H points down, away from a viewer above. Place C3 at the top of the ring: C2 (previous atom) is at lower left, C4 (next atom) at lower right and the methyl points outward. Seen from above, C2 → C4 → CH3 is counter-clockwise, so the centre is S.