Answer: A, B
Using the Fischer arrangement of the three C-Cl bonds as left or right gives 8 combinations. Rotating the molecule by 180∘ pairs them up, so there are 4 distinct stereoisomers. Two (2R,3r,4S and 2R,3s,4S) are meso, because C3 is pseudoasymmetric there, and the other two are the (2R,4R) and (2S,4S) enantiomers. In the (R,R) isomer the two branches at C3 have the same chirality, so C3 is not stereogenic. The 8 combinations are not all distinct.