A $0.10 M$ sucrose solution is hydrolysed $60%$ at $300 K$ to glucose and fructose ( $C X_{12} H X_{22} O X_{11} + H X_{2} O C X_{6} H X_{12} O X_{6} + C X_{6} H X_{12} O X_{6}$ ; assume no change in volume or in the amount of water). Using $R = 0.0821 L atm mo l^{- 1} K^{- 1}$ , calculate the osmotic pressure of the resulting solution in atm (two decimal places).

Numerical answer type, answer in atm, tolerance 0.01.

Answer: 3.94 atm

Sucrose left

= 0.10 \times 0.40 = 0.040

M. Each reacted sucrose gives two monosaccharide molecules:

2 \times 0.060 = 0.120

M. Total particles

= 0.160

π = 0.160 \times 0.0821 \times 300 = 3.94

atm.