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NEET levelSingle correct optionDifficulty 1 of 3so112

A solution is prepared by dissolving $18 g$ of glucose (molar mass $180 g mo l^{- 1}$ ) in $90 g$ of water (molar mass $18 g mo l^{- 1}$ ). The mole fraction of glucose is closest to

A $0.0196$
B $0.0200$
C $0.167$
D $0.9804$

Answer: A

Mole fraction of solute is

n_{2} / (n_{1} + n_{2})

. Here

n_{2} = 0.10

mol and

n_{1} = 5.00

mol. So

x_{2} = 0.10/5.10 = 0.0196

. The option

n_{2} / n_{1}

ignores the solute in the denominator.

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