Answer: B, C, D
Particle concentrations: left 2×0.10=0.20, right 0.15 mol L−1. They are not isotonic; water flows from the lower particle concentration (right) to the higher (left), so the left level rises. The pressure needed to stop the flow is Δπ=(0.20−0.15)×0.0821×300=1.23 atm.