Ethylene glycol (molar mass 62 g mol^-1) is added to 1.00 kg of water so that the solution freezes at -9.3 degC. Take K_f = 1.86 K kg mol^-1 and treat ethylene glycol as a non-electrolyte. The mass of ethylene glycol required is

JEE Main levelSingle correct optionDifficulty 2 of 3so062

Ethylene glycol (molar mass $62 g mo l^{- 1}$ ) is added to $1.00 kg$ of water so that the solution freezes at $- 9.3^{\circ} C$ . Take $K_{f} = 1.86 K kg mo l^{- 1}$ and treat ethylene glycol as a non-electrolyte. The mass of ethylene glycol required is

Δ T_{f} = 9.3 K

, so

m = 9.3/1.86 = 5.0 mol k g^{- 1}

. For

1.00 kg

water, moles

= 5.0

and mass

= 5.0 \times 62 = 310 g