A solution is prepared by dissolving 12 g of urea (molar mass 60 g mol^-1) in 200 g of water. The normal boiling point of water is 100.00 degC and K_b = 0.52 K kg mol^-1. Find the boiling point of the solution in degC, correct to two decimal places.

JEE Main levelNumerical answerDifficulty 2 of 3so061

A solution is prepared by dissolving $12 g$ of urea (molar mass $60 g mo l^{- 1}$ ) in $200 g$ of water. The normal boiling point of water is $100.00^{\circ} C$ and $K_{b} = 0.52 K kg mo l^{- 1}$ . Find the boiling point of the solution in $^{\circ} C$ , correct to two decimal places.

Numerical answer type, answer in degC, tolerance 0.01.

Molality

= (12/60) /0.200 = 1.00 mol k g^{- 1}

Δ T_{b} = 0.52 \times 1.00 = 0.52 K

, so the boiling point is

100.00 + 0.52 = 100.52^{\circ} C