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JEE Advanced levelNumerical answerDifficulty 3 of 3so049

Pure water has vapour pressure at . A solution is prepared by dissolving of urea (molar mass ) and of glucose (molar mass ), both non-volatile non-electrolytes, in of water (molar mass ). Calculate the lowering of vapour pressure in mmHg to two decimal places.

Numerical answer type, answer in mmHg, tolerance 0.005.

Answer: 0.33 mmHg

Moles: urea , glucose , so ; water . . , i.e. 0.33.
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