Numerical answer type, answer in g/mol, tolerance 0.5.
Answer: 55 g/mol
Total loss =3.929+0.071=4.000 g, so (p0−p)/p0=0.071/4.000=0.01775. This equals x2=n2/(n1+n2) with n1=5.00, so n2=rn1/(1−r)=0.09035 mol. M=5.0/0.09035=55.34, about 55 g/mol.