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JEE Main levelSingle correct optionDifficulty 2 of 3so009

$100 mL$ of $0.20 M$ $NaCl$ solution is mixed with $300 mL$ of $0.40 M$ $NaCl$ solution (volumes assumed additive). The molarity of the final solution is

A $0.30 M$
B $0.25 M$
C $0.35 M$
D $0.60 M$

Answer: C

Total moles

= 0.20 \times 0.100 + 0.40 \times 0.300 = 0.14 mol

in

0.400 L

. Molarity

= 0.14/0.400 = 0.35 M

. The simple average

0.30

ignores the different volumes.

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