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Concentration units and Henry's law
NEET level
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Difficulty 1 of 3
so004
The molality of a solution containing
4
g
of
NaOH
(molar mass
40
g
mo
l
−
1
) in
250
g
of water is
A
0.1
m
B
0.4
m
C
16.0
m
D
0.025
m
Answer: B
Moles of NaOH
=
4/40
=
0.10
. Molality
=
moles per kg solvent
=
0.10/0.250
=
0.4
m
.
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