Gas X and gas Y have Henry's law constants K_H = 2 kbar and 40 kbar respectively in water at 298 K (law written as p = K

Question

Gas X and gas Y have Henry's law constants K_H = 2 kbar and 40 kbar respectively in water at 298 K (law written as p = K_H x). At the same partial pressure and temperature, which statement is correct?

Accepted Answer

The mole fraction of X in solution is 20 times that of Y

Answer

The mole fraction of Y in solution is 20 times that of X

Answer

X and Y dissolve to the same extent

Answer

The mole fraction of X in solution is 2 times that of Y

Gas X and gas Y have Henry's law constants $K_{H} = 2 kbar$ and $40 kbar$ respectively in water at $298 K$ (law written as $p = K_{H} x$ ). At the same partial pressure and temperature, which statement is correct?

Answer: D

More questions on Concentration units and Henry's law

Gas X and gas Y have Henry's law constants KH​=2 kbar and 40 kbar respectively in water at 298 K (law written as p=KH​x). At the same partial pressure and temperature, which statement is correct?

Answer: D

More questions on Concentration units and Henry's law

Gas X and gas Y have Henry's law constants $K_{H} = 2 kbar$ and $40 kbar$ respectively in water at $298 K$ (law written as $p = K_{H} x$ ). At the same partial pressure and temperature, which statement is correct?