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JEE Main levelSingle correct optionDifficulty 2 of 3ss170

An ionic solid $MX$ has $r_{+} = 95 pm$ and $r_{-} = 181 pm$ . Using the radius ratio rule, the structure and the coordination number of the cation are

Atrigonal planar, 3
Boctahedral, 6
Ccubic, 8
Dtetrahedral, 4

Answer: B

The radius ratio

r_{+} / r_{-} = 95/181 = 0.525

. This lies in the range 0.414 to 0.732, which corresponds to an octahedral arrangement, so the coordination number is 6.

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