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JEE Main levelSingle correct optionDifficulty 2 of 3ss080

In an ionic solid the cation radius is $95 pm$ and the anion radius is $181 pm$ . Using the ranges 0.225-0.414 (CN 4), 0.414-0.732 (CN 6) and 0.732-1.0 (CN 8), the cation coordination number is

A6
B4
C8
D3

Answer: A

r_{+} / r_{-} = 95/181 = 0.525

, which lies in 0.414-0.732, so the cation sits in an octahedral void with CN 6.

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