MolSynapsequestion bank

MolSynapse / Question bank / Solid State / Close packing, voids and radius ratio

JEE Main levelSingle correct optionDifficulty 2 of 3ss078

Anions of radius $181 pm$ form a ccp lattice. The radius of the largest sphere that fits into an octahedral void (take $r_{void} / r = 0.414$ ) is, in pm,

A40.7
B132.5
C74.9
D106.1

Answer: C

r_{void} = 0.414 \times 181 = 74.9 pm

.

Practice Solid State More on Close packing, voids and radius ratio

Previous questionNext question

More questions on Close packing, voids and radius ratio

In a close-packed structure of N identical spheres, the number of tetrahedral voids is NEET level
The coordination number of an atom in hexagonal close packing (hcp) is NEET level
A radius ratio r_+/r_- in the range 0.414 to 0.732 corresponds to which coordination number and void? NEET level
A close-packed solid contains 0.25 mol of atoms. Using N_A=6.022x10^23 mol^-1, the number of tetrahedral voids present is JEE Main level
In an ionic solid the cation radius is 95 pm and the anion radius is 181 pm. Using the ranges 0.225-0.414 (CN 4), 0.414-0.732 (CN 6) and 0.7... JEE Main level
Anions X form a ccp lattice and cations B occupy two-thirds of the octahedral voids. The formula of the compound is JEE Main level