Answer: A, B, C
The compound is butane-1,2,3-triol. Cleavage of C1-C2 gives HCHO and CHX3CH(OH)CHO; this alpha-hydroxy aldehyde is cleaved to CHX3CHO and HCOOH. Two moles of HIOX4 are used and the products are HCHO, CHX3CHO and HCOOH; no ethanoic acid is formed because the methyl-bearing carbinol carbon becomes an aldehyde, not an acid.