Answer: A, B, C
Mg(Hg) couples ketyl radicals, so acetone gives pinacol. Bouveault-Blanc reduction gives the primary alcohol, and an intramolecular acyloin condensation of the six-carbon diester gives 2-hydroxycyclohexanone. Benzaldehyde under Mg(Hg) couples similarly to hydrobenzoin (1,2-diphenylethane-1,2-diol), not benzyl alcohol.