Answer: A, B, C
Benzene gives the 1,4-diene, donors like OMe remain on sp2 carbons, and the acceptor COOH ends up on an sp3 carbon. An alkyl group such as tert-butyl is a donor, so it stays on a double-bond carbon and the product is 1-tert-butylcyclohexa-1,4-diene. Hence option 4 is wrong.