Answer: A
In an aprotic solvent sodium reduces two ester groups by electron transfer and couples them to an enediolate, which on workup tautomerises to the alpha-hydroxy ketone. Two CX3HX7CO units are joined, giving CX3HX7−CO−CH(OH)−CX3HX7, which is 5-hydroxyoctan-4-one. The diol would need a protic medium or Mg/Hg type coupling of a ketone, and the dione needs oxidation.