One mole of erythritol, $\mathrm{HOCH}{}_2-\mathrm{CHOH}-\mathrm{CHOH}-\mathrm{CH}{}_2\mathrm{OH}$, is treated with excess $\mathrm{HIO}{}_4$. Which statements are correct?

The four carbons are oxygenated and adjacent, so there are 3 C-C bonds and 3 mol of $\mathrm{HIO}{}_4$ are used. The two terminal $\mathrm{CH}{}_2\mathrm{OH}$ groups give 2 $\mathrm{HCHO}$ and the two inner $\mathrm{CHOH}$ carbons give 2 $\mathrm{HCOOH}$. No carbonyl-bearing inner carbon exists, so no $\mathrm{CO}{}_2$ forms. Statements 1, 2 and 3 are correct.