Open-chain D-fructose, HOCH2-CO-(CHOH)3-CH2OH, is treated with excess HIO4. The moles of HIO4 consumed and the products per mole of fructose are

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Open-chain D-fructose, $HOCH X_{2} - CO - (CHOH) X_{3} - CH X_{2} OH$ , is treated with excess $HIO X_{4}$ . The moles of $HIO X_{4}$ consumed and the products per mole of fructose are

All six carbons are oxygenated, so 5 C-C bonds are cleaved and 5 mol of

HIO X_{4}

are used. The two terminal

CH X_{2} OH

groups give 2

HCHO

, the three

CHOH

carbons give 3

HCOOH

, and the ketone carbon, cleaved on both sides, becomes

CO X_{2}