JEE Advanced levelSingle correct optionDifficulty 3 of 3ro051
N-Methylacetamide, CHX3CO−NH−CHX3, is (i) refluxed with dilute HCl to give P (organic products) and (ii) treated separately with excess LiAlHX4 followed by water to give Q. P and Q are respectively
Aacetamide and methanol; ethanol
Bacetic acid and methylammonium chloride; N-methylethanamine
Cacetic acid and methylamine (free base); N-methylacetamide
Dacetaldehyde and methylammonium chloride; ethanamine
Answer: B
(i) Amide hydrolysis gives CHX3COOH and CHX3NHX3X+ClX−. (ii) LiAlHX4 reduces C=O to CHX2, giving CHX3CHX2NHCHX3, N-methylethanamine.