JEE Main levelSingle correct optionDifficulty 2 of 3ro005
Methyl pent-4-enoate, CHX2=CH−CHX2−CHX2−COOCHX3, is shaken with HX2 (1 atm) over Pd-C at room temperature until uptake stops. The product is
Apentan-1-ol
Bmethyl pentanoate
Cpent-4-en-1-ol
Dmethyl pent-4-enoate (no reaction)
Answer: B
Pd-C at 1 atm readily saturates an isolated C=C but does not reduce an ester. Hence CHX2=CH−(CHX2)X2−COOCHX3CHX3CHX2CHX2CHX2COOCHX3, methyl pentanoate.