3.675 g of $K X_{2} Cr X_{2} O X_{7}$ (molar mass 294) is dissolved in water to make 250 mL of solution. Find the normality of this solution when used as an oxidant in acidic medium (reduction to $Cr X^{3 +}$ ), to two decimal places.

Numerical answer type, answer in N, tolerance 0.005.

Answer: 0.3 N

Molarity = (3.675/294)/0.250 = 0.050 M. n-factor = 6, so normality = 0.050 x 6 = 0.30 N.