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JEE Main levelSingle correct optionDifficulty 2 of 3rx177

25 mL of 0.1 N oxalic acid is titrated with 0.02 M $KMnO X_{4}$ in acidic medium. The volume of permanganate needed is:

A $62.5$ mL
B $5$ mL
C $50$ mL
D $25$ mL

Answer: D

Normality of

KMnO X_{4}

=

0.02 \times 5 = 0.10

N.

N_{1} V_{1} = N_{2} V_{2}

gives

V = 25 \times 0.1/0.1 = 25

mL.

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