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NEET levelSingle correct optionDifficulty 1 of 3rx174

In acidic medium, 25 mL of 0.02 M $KMnO X_{4}$ can oxidise how many millimoles of $Fe X^{2 +}$ to $Fe X^{3 +}$ ?

A $2.5$
B $0.5$
C $1.5$
D $5.0$

Answer: A

mmol of

MnO X_{4} X^{-}

=

25 \times 0.02 = 0.5

. Each takes 5 electrons and each

Fe X^{2 +}

gives 1, so mmol of

Fe X^{2 +}

=

0.5 \times 5 = 2.5

.

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