JEE Advanced levelSingle correct optionDifficulty 3 of 3rx150
Use Fe = 56, S = 32, O = 16. A solution contains 0.02 mol KMnOX4 and 0.01 mol KX2CrX2OX7 acidified with HX2SOX4. The mass of FeSOX4 (to FeX3+) that this oxidant mixture can oxidise completely (to MnX2+ and CrX3+) is:
A24.32 g
B19.76 g
C4.56 g
D16.72 g
Answer: A
Equivalents of oxidants: 0.02×5+0.01×6=0.16. Equal equivalents of FeSOX4 (n=1) =0.16 mol. Mass =0.16×152=24.32g.