In acidic solution KMnO4 oxidises both Fe^2+ (to Fe^3+) and C2O4^2- (to CO2) of ferrous oxalate, FeC2O4. The moles of KMnO4 needed for 0.3 mol of FeC2O4 are:

JEE Main levelSingle correct optionDifficulty 2 of 3rx123

In acidic solution $KMnO X_{4}$ oxidises both $Fe X^{2 +}$ (to $Fe X^{3 +}$ ) and $C X_{2} O X_{4} X^{2 -}$ (to $CO X_{2}$ ) of ferrous oxalate, $FeC X_{2} O X_{4}$ . The moles of $KMnO X_{4}$ needed for $0.3$ mol of $FeC X_{2} O X_{4}$ are:

n

-factor of

FeC X_{2} O X_{4}

= 1 (Fe) + 2 (oxalate) = 3. Equivalents

= 0.3 \times 3 = 0.9

. Moles of

KMnO X_{4}

= 0.9/5 = 0.18