In neutral medium MnO4- is reduced to MnO2. The number of equivalents in 0.2 mol of KMnO4 reacting in neutral medium is:

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In neutral medium $MnO X_{4} X^{-}$ is reduced to $MnO X_{2}$ . The number of equivalents in $0.2$ mol of $KMnO X_{4}$ reacting in neutral medium is:

Mn goes from +7 to +4, so

n = 3

. Equivalents

= 0.2 \times 3 = 0.6