In the half-reaction Cr2O7^2- arrow Cr^3+ in acidic medium, the number of H2O molecules formed per Cr2O7^2- in the balanced half-reaction is

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In the half-reaction $Cr X_{2} O X_{7} X^{2 -} \to Cr X^{3 +}$ in acidic medium, the number of $H X_{2} O$ molecules formed per $Cr X_{2} O X_{7} X^{2 -}$ in the balanced half-reaction is

The half-reaction is

Cr X_{2} O X_{7} X^{2 -} + 14 H X^{+} + 6 e X^{-} 2 Cr X^{3 +} + 7 H X_{2} O

. The 7 oxygen atoms of dichromate end up in 7 water molecules, using 14

H X^{+}

. So 7

H X_{2} O

are formed.