In acidic medium FeC2O4 is oxidised by MnO4^-, with Fe^2+ going to Fe^3+ and oxalate going to CO2. The n-factor of FeC2O4 in this reaction is

JEE Main levelSingle correct optionDifficulty 2 of 3rx094

In acidic medium $FeC X_{2} O X_{4}$ is oxidised by $MnO X_{4} X^{-}$ , with $Fe X^{2 +}$ going to $Fe X^{3 +}$ and oxalate going to $CO X_{2}$ . The n-factor of $FeC X_{2} O X_{4}$ in this reaction is

Fe X^{2 +}

Fe X^{3 +}

loses 1 electron, and the two C atoms of oxalate (+3 to +4) lose 2 electrons in total. So n-factor = 1 + 2 = 3.