For the reaction 2MnO4^- + 5H2O2 + 6H^+ -> 2Mn^2+ + 5O2 + 8H2O, select ALL correct statements.

H2O2 acts as the reducing agent

10 electrons are transferred in the equation as written

6 H^+ are consumed per 2 MnO4^- reduced

H2O2 acts as the reducing agent

10 electrons are transferred in the equation as written

6 H^+ are consumed per 2 MnO4^- reduced

The oxygen atoms of the O2 produced come from MnO4^-

JEE Advanced levelOne or more correct optionsDifficulty 3 of 3rx091

For the reaction $2 MnO X_{4} X^{-} + 5 H X_{2} O X_{2} + 6 H X^{+} 2 Mn X^{2 +} + 5 O X_{2} + 8 H X_{2} O$ , select ALL correct statements.

Mn goes +7 to +2 (5 electrons each, 10 for two) and O goes -1 to 0 in

H X_{2} O X_{2}

(2 electrons per molecule, 10 for five), so statements 1 and 2 hold. The equation shows 6

H X^{+}

consumed. The

O X_{2}

comes entirely from

H X_{2} O X_{2}

(the peroxide O-O bond is not broken), so statement 4 is false.