For the reaction Cr2O7^2- + Fe^2+ + H^+ -> Cr^3+ + Fe^3+ + H2O in acidic medium, the coefficient of H^+ in the balanced equation (smallest whole numbers) is

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For the reaction $Cr X_{2} O X_{7} X^{2 -} + Fe X^{2 +} + H X^{+} Cr X^{3 +} + Fe X^{3 +} + H X_{2} O$ in acidic medium, the coefficient of $H X^{+}$ in the balanced equation (smallest whole numbers) is

Two Cr atoms each gain 3 electrons (total 6) and each Fe loses 1, so 6

Fe X^{2 +}

are used. Charge balance (left

- 2 + 12 + x

, right

6 + 18

) and O balance give

x = 14

. The balanced equation is

Cr X_{2} O X_{7} X^{2 -} + 6 Fe X^{2 +} + 14 H X^{+} 2 Cr X^{3 +} + 6 Fe X^{3 +} + 7 H X_{2} O