In acidic medium the reaction MnO4^- + Fe^2+ + H^+ -> Mn^2+ + Fe^3+ + H2O is balanced with the smallest whole-number coefficients. The coefficient of Fe^2+ is

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In acidic medium the reaction $MnO X_{4} X^{-} + Fe X^{2 +} + H X^{+} Mn X^{2 +} + Fe X^{3 +} + H X_{2} O$ is balanced with the smallest whole-number coefficients. The coefficient of $Fe X^{2 +}$ is

Mn changes from +7 to +2 (gain of 5 electrons) and Fe from +2 to +3 (loss of 1 electron), so 5

Fe X^{2 +}

are needed per

MnO X_{4} X^{-}

. Balancing charge with

H X^{+}

and O with

H X_{2} O

gives

MnO X_{4} X^{-} + 5 Fe X^{2 +} + 8 H X^{+} Mn X^{2 +} + 5 Fe X^{3 +} + 4 H X_{2} O

. The coefficient of

Fe X^{2 +}

is 5.