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JEE Main levelSingle correct optionDifficulty 2 of 3rx061

In the reaction $SnCl X_{2} + 2 HgCl X_{2} SnCl X_{4} + Hg X_{2} Cl X_{2}$ , the reducing agent and the reduced product are respectively

A $SnCl X_{2}$ and $Hg X_{2} Cl X_{2}$
B $HgCl X_{2}$ and $SnCl X_{4}$
C $SnCl X_{4}$ and $HgCl X_{2}$
D $Hg X_{2} Cl X_{2}$ and $SnCl X_{2}$

Answer: A

Sn goes from +2 to +4 so

SnCl X_{2}

is oxidised and is the reducing agent. Hg goes from +2 to +1 so

HgCl X_{2}

is reduced to

Hg X_{2} Cl X_{2}

, the reduced product.

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