The inversion temperature of a gas is $1030 K$ and its van der Waals constant $a = 0.364 Pa m^{6} mo l^{- 2}$ . Using $T_{i} = 2 a / R b$ and $R = 8.314 J K^{- 1} mo l^{- 1}$ , the value of $b$ in $c m^{3} mo l^{- 1}$ (one decimal) is

Numerical answer type, answer in cm^3/mol, tolerance 0.2.

Answer: 85 cm^3/mol

b = \frac{2 a}{R T _{i}} = \frac{2 \times 0.364}{8.314 \times 1030} = \frac{0.728}{8563.4} = 8.5013 e - 05 m^{3} mo l^{- 1} = 85.01 c m^{3} mo l^{- 1}

, i.e.

85.0 c m^{3} mo l^{- 1}