The Boyle temperature of nitrogen calculated from its van der Waals constants is $433 K$ . The corresponding critical temperature in K (one decimal) is

Numerical answer type, answer in K, tolerance 0.2.

Answer: 128.3 K

T_{c} = \frac{8 a}{27 R b} = \frac{8}{27} T_{B} = \frac{8 \times 433}{27} = 128.30 K

, i.e.

128.3 K

. The experimental

T_{c}

of nitrogen is

126 K