Answer: A, B, C
Substituting P=VmRT(1+VmB+…) into the pressure series and matching powers of 1/Vm gives B′=B/RT and C′=(C−B2)/(RT)2 (A and B true). Since B′∝B, both are zero at the Boyle temperature (C true). C′ can be negative when B2 exceeds C, which happens for many gases at low temperature (D false).